# NCERT Maths Class 7 Chapter 4 Simple Equations Exercise 4.1 Problems

Maths is a very easy and interesting subject. Everyone will have some kind of fear of this subject but if we understand its very easy subject. This chapter of simple equations is very easy; it is totally based on equations and formulas. If we learn formulas and understand the concept it’s very easy to learn this maths subject. So now we are going to discuss chapter 4 simple equations exercise 4.1 problems.

### 1. By using trial and error method solve the following equations:

a) 5p+2=17
Sol: LHS=5p+2
By subtracting the value of p=0
Then,
LHS=5p+2
=(5×0)+2
=0+2
=2
By comparing LHS and RHS
2≠17
LHS≠RHS
Hence, the value of p=0 is not a solution to the given equation
Let, p=1
LHS=5p+2
=(5×1)+2
=5+2
=7
By comparing LHS and RHS
7≠17
LHS≠RHS
Hence, the value of p=1 is not a solution to the given equation
Let, p=2
LHS=5p+2
=(5×2)+2
=10+2
=12
By comparing LHS and RHS
12≠17
LHS≠RHS
Hence, the value of p=2 is not a solution to the given equation
Let, p=3
LHS=5p+2
=(5×3)+2
=15+2
=17
By comparing LHS and RHS
17=17
LHS=RHS

Hence, the value of p=3 is a solution to the given equation.

## So now we give you some problems related to this topic and try to solve them

### 2. 3m-14=4

Solutio:
LHS=3m-14
By subtracting the value of m=3
Then,
LHS=3m-14
=(3×3)-14
=9-14
=-5
By comparing LHS and RHS
-5≠4
LHS≠RHS
Hence, the value of m=3 is not a solution to the given equation.
Let, m=4
LHS=3m-14
=(3×4)-14
=12-14
= -2
By comparing LHS and RHS
2≠4
LHS≠RHS
Hence, the value of m=4 is not a solution for the given equation.
Let, m=5
LHS=3m-14
=(3×5)-14
=15-14
=1
By comparing LHS and RHS
1≠ 4
LHS≠RHS
Hence, the value of m=5 is not a solution for the given equation.
Let, m=6
LHS=3m-14
=(3×6)-14
=18-14
=4
By comparing LHS and RHS
4=4
LHS=RHS
Hence, the value of m=6 is a solution for the given equation.

### 3. Set up an equation in the following cases:

a) Irfan said he had 7 balls, more than five times the permit marbles. Irfan has 37 marbles. (Take m as the number of parmite balls)
Solutio:
Given,
Number of parameters marbles=m
Then,
Irfan is having 7 marbles more than five times of the marbles parmit have
=5xnumber of parmit’s marbles+7=Total number of marbles irfan having
=(5xm)+7=37
=5m+7=37

b) Laxmi’s father is 49 years old. He is 4 years older than Laxmi three times. (Bring Laxmi’s age to y years)
Solutio:
Given,
Let laxmi’s age to be=y years old
Then,
Laxmi’s father is 4 years older than three times of her age
=3xlaxmi’s age+4=Age of laxmi’s father
=(3xy)+4=49
=3y+4=49

c) The teacher tells the class that the highest score students receive in their class is twice as low as the lowest score plus 7. The highest score is 87. (Take the lowest score for me.)
Solutio:
Given,
Highest score in the class=87
Let lowest score be I
= 2xlowest score +7=highest score in the class
= (2xI)+7=87
=2l+7=87

d) In an isosceles triangle, the vertex angles are twice the principal angles (leave the main angles in degrees. Remember that the angles for a triangle are 180 degrees).
Solutio:
Given,
We know that, the sum of angles of a triangle is 1800
Let base angle be b
Then,
Vertex angle=2xbase angle=2b
=b+b+2b=180°
=4b=180°

#### Conclusion:

These are some of the questions given to you to try to solve them very easy problems. These are some of the basics for this chapter. It’s very important to learn. It’s very essential. Trying to solve all problems all are very easy. Just if we understand the concept we can do it very easily. Maths is a very easy subject.